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13213032434177 is a prime number
BaseRepresentation
bin1100000001000110011000…
…0110101100101000000001
31201210011010221121110120012
43000101212012230220001
53212440242300343202
644033552220554305
72532416155410332
oct300214606545001
951704127543505
1013213032434177
114234685389654
1215949359b2995
1374aca2cc41b4
1433972acb6289
1517da7bd18152
hexc04661aca01

13213032434177 has 2 divisors, whose sum is σ = 13213032434178. Its totient is φ = 13213032434176.

The previous prime is 13213032434143. The next prime is 13213032434267. The reversal of 13213032434177 is 77143423031231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11928983114896 + 1284049319281 = 3453836^2 + 1133159^2 .

It is a cyclic number.

It is not a de Polignac number, because 13213032434177 - 230 = 13211958692353 is a prime.

It is a super-2 number, since 2×132130324341772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13213032434377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606516217088 + 6606516217089.

It is an arithmetic number, because the mean of its divisors is an integer number (6606516217089).

Almost surely, 213213032434177 is an apocalyptic number.

It is an amenable number.

13213032434177 is a deficient number, since it is larger than the sum of its proper divisors (1).

13213032434177 is an equidigital number, since it uses as much as digits as its factorization.

13213032434177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 254016, while the sum is 41.

The spelling of 13213032434177 in words is "thirteen trillion, two hundred thirteen billion, thirty-two million, four hundred thirty-four thousand, one hundred seventy-seven".