Base | Representation |
---|---|
bin | 1100000001000110011000… |
… | …0110101100101000111010 |
3 | 1201210011010221121110122022 |
4 | 3000101212012230220322 |
5 | 3212440242300343414 |
6 | 44033552220554442 |
7 | 2532416155410443 |
oct | 300214606545072 |
9 | 51704127543568 |
10 | 13213032434234 |
11 | 42346853896a6 |
12 | 15949359b2a22 |
13 | 74aca2cc4229 |
14 | 33972acb62ca |
15 | 17da7bd1818e |
hex | c04661aca3a |
13213032434234 has 4 divisors (see below), whose sum is σ = 19819548651354. Its totient is φ = 6606516217116.
The previous prime is 13213032434177. The next prime is 13213032434267. The reversal of 13213032434234 is 43243423031231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12781518765625 + 431513668609 = 3575125^2 + 656897^2 .
It is a super-2 number, since 2×132130324342342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13213032434194 and 13213032434203.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303258108557 + ... + 3303258108560.
Almost surely, 213213032434234 is an apocalyptic number.
13213032434234 is a deficient number, since it is larger than the sum of its proper divisors (6606516217120).
13213032434234 is an equidigital number, since it uses as much as digits as its factorization.
13213032434234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6606516217119.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 13213032434234 its reverse (43243423031231), we get a palindrome (56456455465465).
The spelling of 13213032434234 in words is "thirteen trillion, two hundred thirteen billion, thirty-two million, four hundred thirty-four thousand, two hundred thirty-four".
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