Base | Representation |
---|---|
bin | 11000100111000111… |
… | …10011010111000011 |
3 | 1021002211200201011022 |
4 | 30103203303113003 |
5 | 204030020220103 |
6 | 10023041340055 |
7 | 645301052333 |
oct | 142343632703 |
9 | 37084621138 |
10 | 13213054403 |
11 | 567047437a |
12 | 268903762b |
13 | 1327579bb3 |
14 | 8d4b890c3 |
15 | 524ed9138 |
hex | 3138f35c3 |
13213054403 has 2 divisors, whose sum is σ = 13213054404. Its totient is φ = 13213054402.
The previous prime is 13213054373. The next prime is 13213054409. The reversal of 13213054403 is 30445031231.
It is a strong prime.
It is an emirp because it is prime and its reverse (30445031231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13213054403 - 210 = 13213053379 is a prime.
It is not a weakly prime, because it can be changed into another prime (13213054409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606527201 + 6606527202.
It is an arithmetic number, because the mean of its divisors is an integer number (6606527202).
Almost surely, 213213054403 is an apocalyptic number.
13213054403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213054403 is an equidigital number, since it uses as much as digits as its factorization.
13213054403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 13213054403 its reverse (30445031231), we get a palindrome (43658085634).
The spelling of 13213054403 in words is "thirteen billion, two hundred thirteen million, fifty-four thousand, four hundred three".
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