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132133032031249 is a prime number
BaseRepresentation
bin11110000010110010011110…
…011011111111010000010001
3122022211210110012002112022101
4132002302132123333100101
5114304331422144444444
61145005024341040401
736555203465625244
oct3602623633772021
9568753405075271
10132133032031249
1139113338976097
12129a03250b6101
135896125c0bcc2
14248b3b6a9b25b
15104213b6a93d4
hex782c9e6ff411

132133032031249 has 2 divisors, whose sum is σ = 132133032031250. Its totient is φ = 132133032031248.

The previous prime is 132133032031207. The next prime is 132133032031283. The reversal of 132133032031249 is 942130230331231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101398958787025 + 30734073244224 = 10069705^2 + 5543832^2 .

It is an emirp because it is prime and its reverse (942130230331231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132133032031249 - 245 = 96948659942417 is a prime.

It is not a weakly prime, because it can be changed into another prime (132133032041249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066516015624 + 66066516015625.

It is an arithmetic number, because the mean of its divisors is an integer number (66066516015625).

Almost surely, 2132133032031249 is an apocalyptic number.

It is an amenable number.

132133032031249 is a deficient number, since it is larger than the sum of its proper divisors (1).

132133032031249 is an equidigital number, since it uses as much as digits as its factorization.

132133032031249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 37.

The spelling of 132133032031249 in words is "one hundred thirty-two trillion, one hundred thirty-three billion, thirty-two million, thirty-one thousand, two hundred forty-nine".