Base | Representation |
---|---|
bin | 111101100001111001… |
… | …1001101111010011011 |
3 | 110122001122102210111012 |
4 | 1323003303031322123 |
5 | 4131102301033311 |
6 | 140411310124135 |
7 | 12355255326332 |
oct | 1730363157233 |
9 | 418048383435 |
10 | 132134002331 |
11 | 51046221721 |
12 | 217374b064b |
13 | c5ca0392c6 |
14 | 6576a86d19 |
15 | 368539578b |
hex | 1ec3ccde9b |
132134002331 has 2 divisors, whose sum is σ = 132134002332. Its totient is φ = 132134002330.
The previous prime is 132134002291. The next prime is 132134002337. The reversal of 132134002331 is 133200431231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132134002331 - 218 = 132133740187 is a prime.
It is a super-2 number, since 2×1321340023312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132134002297 and 132134002306.
It is not a weakly prime, because it can be changed into another prime (132134002337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66067001165 + 66067001166.
It is an arithmetic number, because the mean of its divisors is an integer number (66067001166).
Almost surely, 2132134002331 is an apocalyptic number.
132134002331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132134002331 is an equidigital number, since it uses as much as digits as its factorization.
132134002331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 132134002331 its reverse (133200431231), we get a palindrome (265334433562).
The spelling of 132134002331 in words is "one hundred thirty-two billion, one hundred thirty-four million, two thousand, three hundred thirty-one".
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