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132134002331 is a prime number
BaseRepresentation
bin111101100001111001…
…1001101111010011011
3110122001122102210111012
41323003303031322123
54131102301033311
6140411310124135
712355255326332
oct1730363157233
9418048383435
10132134002331
1151046221721
12217374b064b
13c5ca0392c6
146576a86d19
15368539578b
hex1ec3ccde9b

132134002331 has 2 divisors, whose sum is σ = 132134002332. Its totient is φ = 132134002330.

The previous prime is 132134002291. The next prime is 132134002337. The reversal of 132134002331 is 133200431231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132134002331 - 218 = 132133740187 is a prime.

It is a super-2 number, since 2×1321340023312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132134002297 and 132134002306.

It is not a weakly prime, because it can be changed into another prime (132134002337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66067001165 + 66067001166.

It is an arithmetic number, because the mean of its divisors is an integer number (66067001166).

Almost surely, 2132134002331 is an apocalyptic number.

132134002331 is a deficient number, since it is larger than the sum of its proper divisors (1).

132134002331 is an equidigital number, since it uses as much as digits as its factorization.

132134002331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 132134002331 its reverse (133200431231), we get a palindrome (265334433562).

The spelling of 132134002331 in words is "one hundred thirty-two billion, one hundred thirty-four million, two thousand, three hundred thirty-one".