Base | Representation |
---|---|
bin | 11110000010110011011110… |
… | …110000010110101101001010 |
3 | 122022211220020101120111211111 |
4 | 132002303132300112231022 |
5 | 114304341124421041020 |
6 | 1145005323405320534 |
7 | 36555242310643300 |
oct | 3602633660265512 |
9 | 568756211514744 |
10 | 132134111112010 |
11 | 39113841aa2477 |
12 | 129a058656614a |
13 | 5896268647027 |
14 | 248b47a112270 |
15 | 10421a12abd5a |
hex | 782cdec16b4a |
132134111112010 has 48 divisors (see below), whose sum is σ = 277830275374080. Its totient is φ = 45113570950560.
The previous prime is 132134111112001. The next prime is 132134111112041. The reversal of 132134111112010 is 10211111431231.
It is a super-2 number, since 2×1321341111120102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 564028186 + ... + 564262405.
It is an arithmetic number, because the mean of its divisors is an integer number (5788130736960).
Almost surely, 2132134111112010 is an apocalyptic number.
132134111112010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132134111112010 is an abundant number, since it is smaller than the sum of its proper divisors (145696164262070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132134111112010 is a wasteful number, since it uses less digits than its factorization.
132134111112010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1128290851 (or 1128290844 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 132134111112010 its reverse (10211111431231), we get a palindrome (142345222543241).
The spelling of 132134111112010 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, one hundred eleven million, one hundred twelve thousand, ten".
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