Base | Representation |
---|---|
bin | 11110000010110011100100… |
… | …001101001011011100100001 |
3 | 122022211220110202122020212020 |
4 | 132002303210031023130201 |
5 | 114304341321323213040 |
6 | 1145005340433252053 |
7 | 36555244501123401 |
oct | 3602634415133441 |
9 | 568756422566766 |
10 | 132134202554145 |
11 | 39113889679290 |
12 | 129a05b1104029 |
13 | 58962815824bc |
14 | 248b488316801 |
15 | 10421a9320cd0 |
hex | 782ce434b721 |
132134202554145 has 64 divisors (see below), whose sum is σ = 236695074739200. Its totient is φ = 62401427792640.
The previous prime is 132134202554093. The next prime is 132134202554203. The reversal of 132134202554145 is 541455202431231.
It is not a de Polignac number, because 132134202554145 - 220 = 132134201505569 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 132134202554097 and 132134202554106.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 61200847 + ... + 63323076.
It is an arithmetic number, because the mean of its divisors is an integer number (3698360542800).
Almost surely, 2132134202554145 is an apocalyptic number.
132134202554145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
132134202554145 is a deficient number, since it is larger than the sum of its proper divisors (104560872185055).
132134202554145 is a wasteful number, since it uses less digits than its factorization.
132134202554145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124524110.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 132134202554145 its reverse (541455202431231), we get a palindrome (673589404985376).
The spelling of 132134202554145 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, two hundred two million, five hundred fifty-four thousand, one hundred forty-five".
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