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132138254500673 is a prime number
BaseRepresentation
bin11110000010110111010101…
…101110001000001101000001
3122022212021221011002110112212
4132002313111232020031001
5114304423121123010143
61145011250500431505
736555450062112521
oct3602672556101501
9568767834073485
10132138254500673
1139115578912723
12129a13420a8595
135896778b912b5
14248b75050d681
151042344e07918
hex782dd5b88341

132138254500673 has 2 divisors, whose sum is σ = 132138254500674. Its totient is φ = 132138254500672.

The previous prime is 132138254500669. The next prime is 132138254500709. The reversal of 132138254500673 is 376005452831231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107893778419249 + 24244476081424 = 10387193^2 + 4923868^2 .

It is an emirp because it is prime and its reverse (376005452831231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132138254500673 - 22 = 132138254500669 is a prime.

It is not a weakly prime, because it can be changed into another prime (132138254500573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66069127250336 + 66069127250337.

It is an arithmetic number, because the mean of its divisors is an integer number (66069127250337).

Almost surely, 2132138254500673 is an apocalyptic number.

It is an amenable number.

132138254500673 is a deficient number, since it is larger than the sum of its proper divisors (1).

132138254500673 is an equidigital number, since it uses as much as digits as its factorization.

132138254500673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 50.

The spelling of 132138254500673 in words is "one hundred thirty-two trillion, one hundred thirty-eight billion, two hundred fifty-four million, five hundred thousand, six hundred seventy-three".