Base | Representation |
---|---|
bin | 10011001110101010000… |
… | …101000110100000000011 |
3 | 11200022210020002001220111 |
4 | 103032222011012200003 |
5 | 133122221024031224 |
6 | 2451014024252151 |
7 | 164316506164462 |
oct | 23165205064003 |
9 | 4608706061814 |
10 | 1321408423939 |
11 | 46a451673a3a |
12 | 194121011057 |
13 | 977ba50cc06 |
14 | 47d569369d9 |
15 | 2458d64bd94 |
hex | 133aa146803 |
1321408423939 has 2 divisors, whose sum is σ = 1321408423940. Its totient is φ = 1321408423938.
The previous prime is 1321408423927. The next prime is 1321408423957. The reversal of 1321408423939 is 9393248041231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321408423939 is a prime.
It is a super-2 number, since 2×13214084239392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1321408423892 and 1321408423901.
It is not a weakly prime, because it can be changed into another prime (1321408423639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660704211969 + 660704211970.
It is an arithmetic number, because the mean of its divisors is an integer number (660704211970).
Almost surely, 21321408423939 is an apocalyptic number.
1321408423939 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321408423939 is an equidigital number, since it uses as much as digits as its factorization.
1321408423939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 49.
The spelling of 1321408423939 in words is "one trillion, three hundred twenty-one billion, four hundred eight million, four hundred twenty-three thousand, nine hundred thirty-nine".
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