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13214124311131 is a prime number
BaseRepresentation
bin1100000001001010011100…
…1011111000001001011011
31201210020222001011120011101
43000102213023320021123
53213000011310424011
644034252423412231
72532455214252142
oct300224713701133
951706861146141
1013214124311131
1142350957559a7
121594b9b5b4077
1374b11828c733
143397d1cdc759
1517dae2ae72c1
hexc04a72f825b

13214124311131 has 2 divisors, whose sum is σ = 13214124311132. Its totient is φ = 13214124311130.

The previous prime is 13214124311099. The next prime is 13214124311239. The reversal of 13214124311131 is 13111342141231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13214124311131 - 25 = 13214124311099 is a prime.

It is a super-2 number, since 2×132141243111312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13214124311131.

It is not a weakly prime, because it can be changed into another prime (13214124911131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607062155565 + 6607062155566.

It is an arithmetic number, because the mean of its divisors is an integer number (6607062155566).

Almost surely, 213214124311131 is an apocalyptic number.

13214124311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214124311131 is an equidigital number, since it uses as much as digits as its factorization.

13214124311131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 28.

Adding to 13214124311131 its reverse (13111342141231), we get a palindrome (26325466452362).

The spelling of 13214124311131 in words is "thirteen trillion, two hundred fourteen billion, one hundred twenty-four million, three hundred eleven thousand, one hundred thirty-one".