Base | Representation |
---|---|
bin | 10011001110101011000… |
… | …101000110100000000011 |
3 | 11200022211101122102220212 |
4 | 103032223011012200003 |
5 | 133122234322414110 |
6 | 2451015424024335 |
7 | 164320101611603 |
oct | 23165305064003 |
9 | 4608741572825 |
10 | 1321425201155 |
11 | 46a460092a04 |
12 | 1941267620ab |
13 | 977c0b35467 |
14 | 47d58c62c03 |
15 | 2458ed62e05 |
hex | 133ab146803 |
1321425201155 has 32 divisors (see below), whose sum is σ = 1640657386368. Its totient is φ = 1021031424000.
The previous prime is 1321425201127. The next prime is 1321425201193. The reversal of 1321425201155 is 5511025241231.
It is not a de Polignac number, because 1321425201155 - 224 = 1321408423939 is a prime.
It is a super-3 number, since 3×13214252011553 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 88696667 + ... + 88711563.
It is an arithmetic number, because the mean of its divisors is an integer number (51270543324).
Almost surely, 21321425201155 is an apocalyptic number.
1321425201155 is a deficient number, since it is larger than the sum of its proper divisors (319232185213).
1321425201155 is a wasteful number, since it uses less digits than its factorization.
1321425201155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19247.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 1321425201155 in words is "one trillion, three hundred twenty-one billion, four hundred twenty-five million, two hundred one thousand, one hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •