Base | Representation |
---|---|
bin | 10011001110101011111… |
… | …111001101101111010001 |
3 | 11200022212110022102001000 |
4 | 103032223333031233101 |
5 | 133122302222411103 |
6 | 2451021130332213 |
7 | 164320345240566 |
oct | 23165377155721 |
9 | 4608773272030 |
10 | 1321440435153 |
11 | 46a468748493 |
12 | 19412b88a069 |
13 | 977c403a467 |
14 | 47d5acaa86d |
15 | 24591371aa3 |
hex | 133abfcdbd1 |
1321440435153 has 32 divisors (see below), whose sum is σ = 2131785360000. Its totient is φ = 805814847936.
The previous prime is 1321440435121. The next prime is 1321440435167. The reversal of 1321440435153 is 3515340441231.
1321440435153 is a `hidden beast` number, since 1 + 3 + 21 + 440 + 43 + 5 + 153 = 666.
It is not a de Polignac number, because 1321440435153 - 25 = 1321440435121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1321440439153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44397318 + ... + 44427071.
It is an arithmetic number, because the mean of its divisors is an integer number (66618292500).
Almost surely, 21321440435153 is an apocalyptic number.
It is an amenable number.
1321440435153 is a deficient number, since it is larger than the sum of its proper divisors (810344924847).
1321440435153 is a wasteful number, since it uses less digits than its factorization.
1321440435153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88824446 (or 88824440 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 1321440435153 its reverse (3515340441231), we get a palindrome (4836780876384).
The spelling of 1321440435153 in words is "one trillion, three hundred twenty-one billion, four hundred forty million, four hundred thirty-five thousand, one hundred fifty-three".
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