Base | Representation |
---|---|
bin | 11110000011000010110111… |
… | …101011100011111111000001 |
3 | 122022220110212222221222222121 |
4 | 132003002313223203333001 |
5 | 114310124000131212231 |
6 | 1145021055214404241 |
7 | 36556365640123231 |
oct | 3603026753437701 |
9 | 568813788858877 |
10 | 132150635413441 |
11 | 3911a851592737 |
12 | 129a3818500681 |
13 | 589799cc13598 |
14 | 248c1a6963cc1 |
15 | 104281bd1b311 |
hex | 7830b7ae3fc1 |
132150635413441 has 2 divisors, whose sum is σ = 132150635413442. Its totient is φ = 132150635413440.
The previous prime is 132150635413373. The next prime is 132150635413487. The reversal of 132150635413441 is 144314536051231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107162434021041 + 24988201392400 = 10351929^2 + 4998820^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132150635413441 is a prime.
It is not a weakly prime, because it can be changed into another prime (132150635413141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075317706720 + 66075317706721.
It is an arithmetic number, because the mean of its divisors is an integer number (66075317706721).
Almost surely, 2132150635413441 is an apocalyptic number.
It is an amenable number.
132150635413441 is a deficient number, since it is larger than the sum of its proper divisors (1).
132150635413441 is an equidigital number, since it uses as much as digits as its factorization.
132150635413441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 132150635413441 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred thirty-five million, four hundred thirteen thousand, four hundred forty-one".
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