Base | Representation |
---|---|
bin | 11110000011000011010100… |
… | …010011001011111001110011 |
3 | 122022220112010110110002211012 |
4 | 132003003110103023321303 |
5 | 114310130441041000421 |
6 | 1145021215005541135 |
7 | 36556413560252105 |
oct | 3603032423137163 |
9 | 568815113402735 |
10 | 132151115562611 |
11 | 3911aa78620932 |
12 | 129a39312747ab |
13 | 5897a48538112 |
14 | 248c21062d575 |
15 | 104284906295b |
hex | 7830d44cbe73 |
132151115562611 has 2 divisors, whose sum is σ = 132151115562612. Its totient is φ = 132151115562610.
The previous prime is 132151115562541. The next prime is 132151115562677. The reversal of 132151115562611 is 116265511151231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132151115562611 - 218 = 132151115300467 is a prime.
It is a super-2 number, since 2×1321511155626112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132151115562211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075557781305 + 66075557781306.
It is an arithmetic number, because the mean of its divisors is an integer number (66075557781306).
Almost surely, 2132151115562611 is an apocalyptic number.
132151115562611 is a deficient number, since it is larger than the sum of its proper divisors (1).
132151115562611 is an equidigital number, since it uses as much as digits as its factorization.
132151115562611 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54000, while the sum is 41.
The spelling of 132151115562611 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred fifteen million, five hundred sixty-two thousand, six hundred eleven".
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