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132151131052033 is a prime number
BaseRepresentation
bin11110000011000011010101…
…001110010001100000000001
3122022220112011112121001022111
4132003003111032101200001
5114310131004022131113
61145021220321535321
736556414136023552
oct3603032516214001
9568815145531274
10132151131052033
113911aa86340305
12129a39364a4541
135897a4b7cc462
14248c212702329
15104284a5c213d
hex7830d5391801

132151131052033 has 2 divisors, whose sum is σ = 132151131052034. Its totient is φ = 132151131052032.

The previous prime is 132151131052021. The next prime is 132151131052103. The reversal of 132151131052033 is 330250131151231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131904949360144 + 246181691889 = 11484988^2 + 496167^2 .

It is a cyclic number.

It is not a de Polignac number, because 132151131052033 - 221 = 132151128954881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132151131051986 and 132151131052004.

It is not a weakly prime, because it can be changed into another prime (132151131052133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075565526016 + 66075565526017.

It is an arithmetic number, because the mean of its divisors is an integer number (66075565526017).

Almost surely, 2132151131052033 is an apocalyptic number.

It is an amenable number.

132151131052033 is a deficient number, since it is larger than the sum of its proper divisors (1).

132151131052033 is an equidigital number, since it uses as much as digits as its factorization.

132151131052033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 132151131052033 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty-one million, fifty-two thousand, thirty-three".