Base | Representation |
---|---|
bin | 11110000011000101010111… |
… | …010111010011000111000011 |
3 | 122022220201210201001110111012 |
4 | 132003011113113103013003 |
5 | 114310144442000043003 |
6 | 1145022221115511135 |
7 | 36556522220452031 |
oct | 3603052727230703 |
9 | 568821721043435 |
10 | 132153314456003 |
11 | 391209a6864aa5 |
12 | 129a42457584ab |
13 | 5898008c6cb79 |
14 | 248c37c69d551 |
15 | 10429271118d8 |
hex | 7831575d31c3 |
132153314456003 has 2 divisors, whose sum is σ = 132153314456004. Its totient is φ = 132153314456002.
The previous prime is 132153314455991. The next prime is 132153314456101. The reversal of 132153314456003 is 300654413351231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132153314456003 - 216 = 132153314390467 is a prime.
It is a super-2 number, since 2×1321533144560032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132153314456503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076657228001 + 66076657228002.
It is an arithmetic number, because the mean of its divisors is an integer number (66076657228002).
Almost surely, 2132153314456003 is an apocalyptic number.
132153314456003 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153314456003 is an equidigital number, since it uses as much as digits as its factorization.
132153314456003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 132153314456003 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, three hundred fourteen million, four hundred fifty-six thousand, three".
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