Base | Representation |
---|---|
bin | 111101100010011111… |
… | …1101010101101110111 |
3 | 110122010001010222110122 |
4 | 1323010333222231313 |
5 | 4131122413341010 |
6 | 140413303442155 |
7 | 12355620555563 |
oct | 1730477525567 |
9 | 418101128418 |
10 | 132154043255 |
11 | 5105656a773 |
12 | 2174215635b |
13 | c601235240 |
14 | 65795c26a3 |
15 | 3687003855 |
hex | 1ec4feab77 |
132154043255 has 32 divisors (see below), whose sum is σ = 171813882240. Its totient is φ = 97003468800.
The previous prime is 132154043251. The next prime is 132154043317. The reversal of 132154043255 is 552340451231.
It is not a de Polignac number, because 132154043255 - 22 = 132154043251 is a prime.
It is a super-2 number, since 2×1321540432552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132154043251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9094886 + ... + 9109404.
It is an arithmetic number, because the mean of its divisors is an integer number (5369183820).
Almost surely, 2132154043255 is an apocalyptic number.
132154043255 is a deficient number, since it is larger than the sum of its proper divisors (39659838985).
132154043255 is a wasteful number, since it uses less digits than its factorization.
132154043255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15371.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 132154043255 its reverse (552340451231), we get a palindrome (684494494486).
The spelling of 132154043255 in words is "one hundred thirty-two billion, one hundred fifty-four million, forty-three thousand, two hundred fifty-five".
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