Base | Representation |
---|---|
bin | 11110000011000111001111… |
… | …000111001111001011011001 |
3 | 122022220220222201110001112112 |
4 | 132003013033013033023121 |
5 | 114310213100304332023 |
6 | 1145023152324522105 |
7 | 36556623054240521 |
oct | 3603071707171331 |
9 | 568826881401475 |
10 | 132155323511513 |
11 | 39121837927155 |
12 | 129a4706550335 |
13 | 5898269267c03 |
14 | 248c4cd434681 |
15 | 10429e36b2478 |
hex | 7831cf1cf2d9 |
132155323511513 has 2 divisors, whose sum is σ = 132155323511514. Its totient is φ = 132155323511512.
The previous prime is 132155323511437. The next prime is 132155323511543. The reversal of 132155323511513 is 315115323551231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100570170427024 + 31585153084489 = 10028468^2 + 5620067^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132155323511513 is a prime.
It is not a weakly prime, because it can be changed into another prime (132155323511543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66077661755756 + 66077661755757.
It is an arithmetic number, because the mean of its divisors is an integer number (66077661755757).
Almost surely, 2132155323511513 is an apocalyptic number.
It is an amenable number.
132155323511513 is a deficient number, since it is larger than the sum of its proper divisors (1).
132155323511513 is an equidigital number, since it uses as much as digits as its factorization.
132155323511513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 202500, while the sum is 41.
The spelling of 132155323511513 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, three hundred twenty-three million, five hundred eleven thousand, five hundred thirteen".
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