Base | Representation |
---|---|
bin | 11110000011001000000110… |
… | …000100100010110011100010 |
3 | 122022221000100222102120210022 |
4 | 132003020012010202303202 |
5 | 114310221442330133404 |
6 | 1145023424023233442 |
7 | 36556654651405322 |
oct | 3603100604426342 |
9 | 568830328376708 |
10 | 132156245552354 |
11 | 39122170343081 |
12 | 129a49232a8882 |
13 | 58983852aa8ca |
14 | 248c579a8b282 |
15 | 1042a495e48be |
hex | 783206122ce2 |
132156245552354 has 4 divisors (see below), whose sum is σ = 198234368328534. Its totient is φ = 66078122776176.
The previous prime is 132156245552273. The next prime is 132156245552369. The reversal of 132156245552354 is 453255542651231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 84984005630329 + 47172239922025 = 9218677^2 + 6868205^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 132156245552296 and 132156245552305.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33039061388087 + ... + 33039061388090.
Almost surely, 2132156245552354 is an apocalyptic number.
132156245552354 is a deficient number, since it is larger than the sum of its proper divisors (66078122776180).
132156245552354 is an equidigital number, since it uses as much as digits as its factorization.
132156245552354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66078122776179.
The product of its digits is 21600000, while the sum is 53.
The spelling of 132156245552354 in words is "one hundred thirty-two trillion, one hundred fifty-six billion, two hundred forty-five million, five hundred fifty-two thousand, three hundred fifty-four".
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