Base | Representation |
---|---|
bin | 10011001110110101100… |
… | …101000111000100010101 |
3 | 11200100021200010110020202 |
4 | 103032311211013010111 |
5 | 133123114422123440 |
6 | 2451045115510245 |
7 | 164324341146611 |
oct | 23166545070425 |
9 | 4610250113222 |
10 | 1321601364245 |
11 | 46a540574938 |
12 | 194175758385 |
13 | 9781b494a86 |
14 | 47d743dc341 |
15 | 245a055e615 |
hex | 133b5947115 |
1321601364245 has 4 divisors (see below), whose sum is σ = 1585921637100. Its totient is φ = 1057281091392.
The previous prime is 1321601364131. The next prime is 1321601364253. The reversal of 1321601364245 is 5424631061231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 826050130129 + 495551234116 = 908873^2 + 703954^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321601364245 - 210 = 1321601363221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1321601364199 and 1321601364208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132160136420 + ... + 132160136429.
It is an arithmetic number, because the mean of its divisors is an integer number (396480409275).
Almost surely, 21321601364245 is an apocalyptic number.
It is an amenable number.
1321601364245 is a deficient number, since it is larger than the sum of its proper divisors (264320272855).
1321601364245 is an equidigital number, since it uses as much as digits as its factorization.
1321601364245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264320272854.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 1321601364245 in words is "one trillion, three hundred twenty-one billion, six hundred one million, three hundred sixty-four thousand, two hundred forty-five".
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