Base | Representation |
---|---|
bin | 11110000011010001100011… |
… | …111111001010110111101011 |
3 | 122022221222121102202202122111 |
4 | 132003101203333022313223 |
5 | 114310403302222331431 |
6 | 1145032224443103151 |
7 | 36560464606425004 |
oct | 3603214377126753 |
9 | 568858542682574 |
10 | 132166411136491 |
11 | 39126507573986 |
12 | 129a689b811ab7 |
13 | 5899315392454 |
14 | 248cc61bd41ab |
15 | 1042e41cae7b1 |
hex | 783463fcadeb |
132166411136491 has 2 divisors, whose sum is σ = 132166411136492. Its totient is φ = 132166411136490.
The previous prime is 132166411136399. The next prime is 132166411136497. The reversal of 132166411136491 is 194631114661231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132166411136491 - 237 = 132028972183019 is a prime.
It is not a weakly prime, because it can be changed into another prime (132166411136497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66083205568245 + 66083205568246.
It is an arithmetic number, because the mean of its divisors is an integer number (66083205568246).
Almost surely, 2132166411136491 is an apocalyptic number.
132166411136491 is a deficient number, since it is larger than the sum of its proper divisors (1).
132166411136491 is an equidigital number, since it uses as much as digits as its factorization.
132166411136491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 559872, while the sum is 49.
The spelling of 132166411136491 in words is "one hundred thirty-two trillion, one hundred sixty-six billion, four hundred eleven million, one hundred thirty-six thousand, four hundred ninety-one".
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