Base | Representation |
---|---|
bin | 11000100111100110… |
… | …11100000111000101 |
3 | 1021010010101222000212 |
4 | 30103303130013011 |
5 | 204032042402402 |
6 | 10023305245205 |
7 | 645350644103 |
oct | 142363340705 |
9 | 37103358025 |
10 | 13217153477 |
11 | 5672814040 |
12 | 268a493805 |
13 | 1328383898 |
14 | 8d5534c73 |
15 | 525548952 |
hex | 313cdc1c5 |
13217153477 has 24 divisors (see below), whose sum is σ = 15297714432. Its totient is φ = 11317980800.
The previous prime is 13217153447. The next prime is 13217153491. The reversal of 13217153477 is 77435171231.
13217153477 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13217153477 - 26 = 13217153413 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13217153447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 361868 + ... + 396714.
It is an arithmetic number, because the mean of its divisors is an integer number (637404768).
Almost surely, 213217153477 is an apocalyptic number.
It is an amenable number.
13217153477 is a deficient number, since it is larger than the sum of its proper divisors (2080560955).
13217153477 is a wasteful number, since it uses less digits than its factorization.
13217153477 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34957 (or 34928 counting only the distinct ones).
The product of its digits is 123480, while the sum is 41.
The spelling of 13217153477 in words is "thirteen billion, two hundred seventeen million, one hundred fifty-three thousand, four hundred seventy-seven".
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