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13220103433 is a prime number
BaseRepresentation
bin11000100111111101…
…01100010100001001
31021010022221211121111
430103332230110021
5204033321302213
610023452410321
7645415011415
oct142376542411
937108854544
1013220103433
115674449419
12268b4769a1
131328b77514
148d5aa1d45
1552592ca3d
hex313fac509

13220103433 has 2 divisors, whose sum is σ = 13220103434. Its totient is φ = 13220103432.

The previous prime is 13220103373. The next prime is 13220103443. The reversal of 13220103433 is 33430102231.

13220103433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8873074809 + 4347028624 = 94197^2 + 65932^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13220103433 is a prime.

It is a super-2 number, since 2×132201034332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13220103443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610051716 + 6610051717.

It is an arithmetic number, because the mean of its divisors is an integer number (6610051717).

Almost surely, 213220103433 is an apocalyptic number.

It is an amenable number.

13220103433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220103433 is an equidigital number, since it uses as much as digits as its factorization.

13220103433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13220103433 its reverse (33430102231), we get a palindrome (46650205664).

The spelling of 13220103433 in words is "thirteen billion, two hundred twenty million, one hundred three thousand, four hundred thirty-three".