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132203021030257 is a prime number
BaseRepresentation
bin11110000011110011101010…
…000110110101001101110001
3122100002111002211202001122211
4132003303222012311031301
5114312003241340432012
61145101121320132121
736563232050406112
oct3603635206651561
9570074084661584
10132203021030257
113913aa93933a31
12129b19b8307041
13589c8caca4298
14249093604c209
151043d85d456a7
hex783cea1b5371

132203021030257 has 2 divisors, whose sum is σ = 132203021030258. Its totient is φ = 132203021030256.

The previous prime is 132203021030191. The next prime is 132203021030279. The reversal of 132203021030257 is 752030120302231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104713961544256 + 27489059486001 = 10232984^2 + 5243001^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132203021030257 is a prime.

It is a super-2 number, since 2×1322030210302572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132203021030287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66101510515128 + 66101510515129.

It is an arithmetic number, because the mean of its divisors is an integer number (66101510515129).

Almost surely, 2132203021030257 is an apocalyptic number.

It is an amenable number.

132203021030257 is a deficient number, since it is larger than the sum of its proper divisors (1).

132203021030257 is an equidigital number, since it uses as much as digits as its factorization.

132203021030257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 132203021030257 its reverse (752030120302231), we get a palindrome (884233141332488).

The spelling of 132203021030257 in words is "one hundred thirty-two trillion, two hundred three billion, twenty-one million, thirty thousand, two hundred fifty-seven".