Base | Representation |
---|---|
bin | 1100000001100001100110… |
… | …1111001010011101100111 |
3 | 1201210212000022012201221020 |
4 | 3000120121233022131213 |
5 | 3213100224312143421 |
6 | 44041201343422223 |
7 | 2533065243330552 |
oct | 300303157123547 |
9 | 51725008181836 |
10 | 13220341131111 |
11 | 4237795a07854 |
12 | 15962355b4973 |
13 | 74b89925163a |
14 | 339c2182b699 |
15 | 17dd587acdc6 |
hex | c0619bca767 |
13220341131111 has 8 divisors (see below), whose sum is σ = 17633956385280. Its totient is φ = 8810143315512.
The previous prime is 13220341131097. The next prime is 13220341131187. The reversal of 13220341131111 is 11113114302231.
13220341131111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13220341131111 - 29 = 13220341130599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13220341131211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 854350615 + ... + 854366088.
It is an arithmetic number, because the mean of its divisors is an integer number (2204244548160).
Almost surely, 213220341131111 is an apocalyptic number.
13220341131111 is a deficient number, since it is larger than the sum of its proper divisors (4413615254169).
13220341131111 is a wasteful number, since it uses less digits than its factorization.
13220341131111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1708719285.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 13220341131111 its reverse (11113114302231), we get a palindrome (24333455433342).
The spelling of 13220341131111 in words is "thirteen trillion, two hundred twenty billion, three hundred forty-one million, one hundred thirty-one thousand, one hundred eleven".
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