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13220402512489 is a prime number
BaseRepresentation
bin1100000001100001110101…
…1001010100001001101001
31201210212011120201020100121
43000120131121110021221
53213100341020344424
644041211415203241
72533066620140164
oct300303531241151
951725146636317
1013220402512489
114237817621567
121596252076521
1374b8a8b93293
14339c29a48adb
1517dd5dd84ee4
hexc061d654269

13220402512489 has 2 divisors, whose sum is σ = 13220402512490. Its totient is φ = 13220402512488.

The previous prime is 13220402512399. The next prime is 13220402512531. The reversal of 13220402512489 is 98421520402231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11529861669225 + 1690540843264 = 3395565^2 + 1300208^2 .

It is a cyclic number.

It is not a de Polignac number, because 13220402512489 - 225 = 13220368958057 is a prime.

It is not a weakly prime, because it can be changed into another prime (13220402512189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610201256244 + 6610201256245.

It is an arithmetic number, because the mean of its divisors is an integer number (6610201256245).

Almost surely, 213220402512489 is an apocalyptic number.

It is an amenable number.

13220402512489 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220402512489 is an equidigital number, since it uses as much as digits as its factorization.

13220402512489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 43.

The spelling of 13220402512489 in words is "thirteen trillion, two hundred twenty billion, four hundred two million, five hundred twelve thousand, four hundred eighty-nine".