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132204434024344 = 23111502323113913
BaseRepresentation
bin11110000011110100111110…
…010100111110011110011000
3122100002121202022112121011011
4132003310332110332132120
5114312014140102234334
61145101513433343304
736563312055561313
oct3603647624763630
9570077668477134
10132204434024344
1139140649498340
12129b2131567b34
13589ca94952366
142490a2b98397a
151043e19e05564
hex783d3e53e798

132204434024344 has 16 divisors (see below), whose sum is σ = 270418160504520. Its totient is φ = 60092924556480.

The previous prime is 132204434024339. The next prime is 132204434024389. The reversal of 132204434024344 is 443420434402231.

It is a junction number, because it is equal to n+sod(n) for n = 132204434024297 and 132204434024306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 751161556869 + ... + 751161557044.

Almost surely, 2132204434024344 is an apocalyptic number.

It is an amenable number.

132204434024344 is an abundant number, since it is smaller than the sum of its proper divisors (138213726480176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132204434024344 is a wasteful number, since it uses less digits than its factorization.

132204434024344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1502323113930 (or 1502323113926 counting only the distinct ones).

The product of its (nonzero) digits is 884736, while the sum is 40.

Adding to 132204434024344 its reverse (443420434402231), we get a palindrome (575624868426575).

The spelling of 132204434024344 in words is "one hundred thirty-two trillion, two hundred four billion, four hundred thirty-four million, twenty-four thousand, three hundred forty-four".

Divisors: 1 2 4 8 11 22 44 88 1502323113913 3004646227826 6009292455652 12018584911304 16525554253043 33051108506086 66102217012172 132204434024344