Base | Representation |
---|---|
bin | 11110000011111011010010… |
… | …010111000000011101000000 |
3 | 122100010021020201112111000000 |
4 | 132003323102113000131000 |
5 | 114312122030403131000 |
6 | 1145104554221000000 |
7 | 36563642045242521 |
oct | 3603732227003500 |
9 | 570107221474000 |
10 | 132211212552000 |
11 | 3914350782350a |
12 | 129b35036b3000 |
13 | 58a06050c367a |
14 | 24910b1d2c848 |
15 | 10441b5073000 |
hex | 783ed25c0740 |
132211212552000 has 784 divisors, whose sum is σ = 491917497873984. Its totient is φ = 35183756160000.
The previous prime is 132211212551959. The next prime is 132211212552011. The reversal of 132211212552000 is 255212112231.
132211212552000 is a `hidden beast` number, since 1 + 3 + 2 + 2 + 1 + 12 + 125 + 520 + 0 + 0 = 666.
It is a super-3 number, since 3×1322112125520003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 2863488915 + ... + 2863535085.
Almost surely, 2132211212552000 is an apocalyptic number.
132211212552000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132211212552000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (245958748936992).
132211212552000 is an abundant number, since it is smaller than the sum of its proper divisors (359706285321984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132211212552000 is an frugal number, since it uses more digits than its factorization.
132211212552000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46707 (or 46672 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 132211212552000 its reverse (255212112231), we get a palindrome (132466424664231).
The spelling of 132211212552000 in words is "one hundred thirty-two trillion, two hundred eleven billion, two hundred twelve million, five hundred fifty-two thousand".
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