Base | Representation |
---|---|
bin | 10011001111010100011… |
… | …111100110000100001001 |
3 | 11200101121211001111021101 |
4 | 103033110133212010021 |
5 | 133130200210341131 |
6 | 2451212404141401 |
7 | 164343236451403 |
oct | 23172437460411 |
9 | 4611554044241 |
10 | 1322120012041 |
11 | 46a787308684 |
12 | 19429b397861 |
13 | 978a1a7896a |
14 | 47dc3249b73 |
15 | 245d0d5cc61 |
hex | 133d47e6109 |
1322120012041 has 2 divisors, whose sum is σ = 1322120012042. Its totient is φ = 1322120012040.
The previous prime is 1322120012011. The next prime is 1322120012093. The reversal of 1322120012041 is 1402100212231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1025705098441 + 296414913600 = 1012771^2 + 544440^2 .
It is a cyclic number.
It is not a de Polignac number, because 1322120012041 - 29 = 1322120011529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1322120012011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661060006020 + 661060006021.
It is an arithmetic number, because the mean of its divisors is an integer number (661060006021).
Almost surely, 21322120012041 is an apocalyptic number.
It is an amenable number.
1322120012041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322120012041 is an equidigital number, since it uses as much as digits as its factorization.
1322120012041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1322120012041 its reverse (1402100212231), we get a palindrome (2724220224272).
The spelling of 1322120012041 in words is "one trillion, three hundred twenty-two billion, one hundred twenty million, twelve thousand, forty-one".
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