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132212147095177 is a prime number
BaseRepresentation
bin11110000011111100001010…
…000100000000011010001001
3122100010100122212001012020021
4132003330022010000122021
5114312130434124021202
61145105231043300441
736564004153601302
oct3603741204003211
9570110585035207
10132212147095177
11391439472a9646
12129b372467a721
1358a07238c2bb6
1424911600bb7a9
15104421c124a37
hex783f0a100689

132212147095177 has 2 divisors, whose sum is σ = 132212147095178. Its totient is φ = 132212147095176.

The previous prime is 132212147095159. The next prime is 132212147095253. The reversal of 132212147095177 is 771590741212231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70036461950841 + 62175685144336 = 8368779^2 + 7885156^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132212147095177 is a prime.

It is a super-2 number, since 2×1322121470951772 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132212147095577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106073547588 + 66106073547589.

It is an arithmetic number, because the mean of its divisors is an integer number (66106073547589).

Almost surely, 2132212147095177 is an apocalyptic number.

It is an amenable number.

132212147095177 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212147095177 is an equidigital number, since it uses as much as digits as its factorization.

132212147095177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1481760, while the sum is 52.

The spelling of 132212147095177 in words is "one hundred thirty-two trillion, two hundred twelve billion, one hundred forty-seven million, ninety-five thousand, one hundred seventy-seven".