Base | Representation |
---|---|
bin | 11000101000000110… |
… | …10010111011001001 |
3 | 1021010102020010220211 |
4 | 30110003102323021 |
5 | 204034123411103 |
6 | 10023534321121 |
7 | 645431165512 |
oct | 142403227311 |
9 | 37112203824 |
10 | 13221310153 |
11 | 56750a3007 |
12 | 268b9591a1 |
13 | 13291aa85c |
14 | 8d5cd7a09 |
15 | 525aba36d |
hex | 3140d2ec9 |
13221310153 has 2 divisors, whose sum is σ = 13221310154. Its totient is φ = 13221310152.
The previous prime is 13221310127. The next prime is 13221310171. The reversal of 13221310153 is 35101312231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8395507129 + 4825803024 = 91627^2 + 69468^2 .
It is an emirp because it is prime and its reverse (35101312231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13221310153 is a prime.
It is a super-3 number, since 3×132213101533 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13221310103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610655076 + 6610655077.
It is an arithmetic number, because the mean of its divisors is an integer number (6610655077).
Almost surely, 213221310153 is an apocalyptic number.
It is an amenable number.
13221310153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13221310153 is an equidigital number, since it uses as much as digits as its factorization.
13221310153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13221310153 its reverse (35101312231), we get a palindrome (48322622384).
The spelling of 13221310153 in words is "thirteen billion, two hundred twenty-one million, three hundred ten thousand, one hundred fifty-three".
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