Base | Representation |
---|---|
bin | 11110000011111110110100… |
… | …010111011101101010010011 |
3 | 122100010122000222102101012122 |
4 | 132003332310113131222103 |
5 | 114312202312101304301 |
6 | 1145110422351444455 |
7 | 36564135026615051 |
oct | 3603766427355223 |
9 | 570118028371178 |
10 | 132215004322451 |
11 | 391450831137a6 |
12 | 129b41a152672b |
13 | 58a0a8a83901b |
14 | 249135175b1d1 |
15 | 1044337db581b |
hex | 783fb45dda93 |
132215004322451 has 2 divisors, whose sum is σ = 132215004322452. Its totient is φ = 132215004322450.
The previous prime is 132215004322421. The next prime is 132215004322459. The reversal of 132215004322451 is 154223400512231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132215004322451 - 238 = 131940126415507 is a prime.
It is a super-2 number, since 2×1322150043224512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132215004322459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107502161225 + 66107502161226.
It is an arithmetic number, because the mean of its divisors is an integer number (66107502161226).
Almost surely, 2132215004322451 is an apocalyptic number.
132215004322451 is a deficient number, since it is larger than the sum of its proper divisors (1).
132215004322451 is an equidigital number, since it uses as much as digits as its factorization.
132215004322451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 132215004322451 its reverse (154223400512231), we get a palindrome (286438404834682).
The spelling of 132215004322451 in words is "one hundred thirty-two trillion, two hundred fifteen billion, four million, three hundred twenty-two thousand, four hundred fifty-one".
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