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132215060502619 is a prime number
BaseRepresentation
bin11110000011111110110111…
…101101110001100001011011
3122100010122011220010121220121
4132003332313231301201123
5114312202420442040434
61145110432115534111
736564136311262453
oct3603766755614133
9570118156117817
10132215060502619
11391451018a5796
12129b41b82ba337
1358a0a99379423
142491358dc2d63
15104433ccb17b4
hex783fb7b7185b

132215060502619 has 2 divisors, whose sum is σ = 132215060502620. Its totient is φ = 132215060502618.

The previous prime is 132215060502557. The next prime is 132215060502643. The reversal of 132215060502619 is 916205060512231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132215060502619 - 213 = 132215060494427 is a prime.

It is a super-3 number, since 3×1322150605026193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (132215060502649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107530251309 + 66107530251310.

It is an arithmetic number, because the mean of its divisors is an integer number (66107530251310).

Almost surely, 2132215060502619 is an apocalyptic number.

132215060502619 is a deficient number, since it is larger than the sum of its proper divisors (1).

132215060502619 is an equidigital number, since it uses as much as digits as its factorization.

132215060502619 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 43.

The spelling of 132215060502619 in words is "one hundred thirty-two trillion, two hundred fifteen billion, sixty million, five hundred two thousand, six hundred nineteen".