Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …011011011011010001011011 |
3 | 122100011010020200000021100101 |
4 | 132010003211123123101123 |
5 | 114312243302314141443 |
6 | 1145113030302120231 |
7 | 36564405614636224 |
oct | 3604034533332133 |
9 | 570133220007311 |
10 | 132220122412123 |
11 | 3914726a148279 |
12 | 129b518b580077 |
13 | 58a13c4ca3155 |
14 | 24916b939c24b |
15 | 104453739684d |
hex | 7840e56db45b |
132220122412123 has 2 divisors, whose sum is σ = 132220122412124. Its totient is φ = 132220122412122.
The previous prime is 132220122412093. The next prime is 132220122412171. The reversal of 132220122412123 is 321214221022231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132220122412123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132220122412091 and 132220122412100.
It is not a weakly prime, because it can be changed into another prime (132220122412523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110061206061 + 66110061206062.
It is an arithmetic number, because the mean of its divisors is an integer number (66110061206062).
Almost surely, 2132220122412123 is an apocalyptic number.
132220122412123 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220122412123 is an equidigital number, since it uses as much as digits as its factorization.
132220122412123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 132220122412123 its reverse (321214221022231), we get a palindrome (453434343434354).
The spelling of 132220122412123 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-two million, four hundred twelve thousand, one hundred twenty-three".
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