Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …011110110111000100101011 |
3 | 122100011010020201201000022222 |
4 | 132010003211132313010223 |
5 | 114312243303031444202 |
6 | 1145113030333304255 |
7 | 36564405625406063 |
oct | 3604034536670453 |
9 | 570133221630288 |
10 | 132220123312427 |
11 | 3914726a702727 |
12 | 129b518b93508b |
13 | 58a13c5229b87 |
14 | 24916b95543a3 |
15 | 10445374c34a2 |
hex | 7840e57b712b |
132220123312427 has 2 divisors, whose sum is σ = 132220123312428. Its totient is φ = 132220123312426.
The previous prime is 132220123312373. The next prime is 132220123312451. The reversal of 132220123312427 is 724213321022231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132220123312427 - 210 = 132220123311403 is a prime.
It is a super-2 number, since 2×1322201233124272 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132220123312477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110061656213 + 66110061656214.
It is an arithmetic number, because the mean of its divisors is an integer number (66110061656214).
Almost surely, 2132220123312427 is an apocalyptic number.
132220123312427 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220123312427 is an equidigital number, since it uses as much as digits as its factorization.
132220123312427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 132220123312427 its reverse (724213321022231), we get a palindrome (856433444334658).
The spelling of 132220123312427 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-three million, three hundred twelve thousand, four hundred twenty-seven".
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