Base | Representation |
---|---|
bin | 11110000100000011100110… |
… | …001000000110010001110011 |
3 | 122100011010021111001020010011 |
4 | 132010003212020012101303 |
5 | 114312243313313410421 |
6 | 1145113031401115351 |
7 | 36564406116321463 |
oct | 3604034610062163 |
9 | 570133244036104 |
10 | 132220134122611 |
11 | 39147275816567 |
12 | 129b5193488b57 |
13 | 58a13c7543432 |
14 | 24916bab69ba3 |
15 | 104453840b4e1 |
hex | 7840e6206473 |
132220134122611 has 2 divisors, whose sum is σ = 132220134122612. Its totient is φ = 132220134122610.
The previous prime is 132220134122561. The next prime is 132220134122669. The reversal of 132220134122611 is 116221431022231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132220134122611 - 223 = 132220125734003 is a prime.
It is not a weakly prime, because it can be changed into another prime (132220134122411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110067061305 + 66110067061306.
It is an arithmetic number, because the mean of its divisors is an integer number (66110067061306).
Almost surely, 2132220134122611 is an apocalyptic number.
132220134122611 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220134122611 is an equidigital number, since it uses as much as digits as its factorization.
132220134122611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 132220134122611 its reverse (116221431022231), we get a palindrome (248441565144842).
The spelling of 132220134122611 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred thirty-four million, one hundred twenty-two thousand, six hundred eleven".
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