1322213101333 has 4 divisors (see below), whose sum is σ = 1322222838208. Its totient is φ = 1322203364460.

The previous prime is 1322213101291. The next prime is 1322213101387. The reversal of 1322213101333 is 3331013122231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1322213101333 - 2⁹ = 1322213100821 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1322213101298 and 1322213101307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1322213161333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4661823 + ... + 4937308.

It is an arithmetic number, because the mean of its divisors is an integer number (330555709552).

Almost surely, 2^{1322213101333} is an apocalyptic number.

It is an amenable number.

1322213101333 is a deficient number, since it is larger than the sum of its proper divisors (9736875).

1322213101333 is an equidigital number, since it uses as much as digits as its factorization.

1322213101333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9736874.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1322213101333 its reverse (3331013122231), we get a palindrome (4653226223564).

The spelling of 1322213101333 in words is "one trillion, three hundred twenty-two billion, two hundred thirteen million, one hundred one thousand, three hundred thirty-three".