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13222150555153 is a prime number
BaseRepresentation
bin1100000001101000010110…
…0101100100011000010001
31201211000200101222000002111
43000122011211210120101
53213112431020231103
644042101101545321
72533161134225401
oct300320545443021
951730611860074
1013222150555153
114238534318921
12159665b575241
1374bac7091057
14339d53c78801
1517de1257886d
hexc0685964611

13222150555153 has 2 divisors, whose sum is σ = 13222150555154. Its totient is φ = 13222150555152.

The previous prime is 13222150555121. The next prime is 13222150555169. The reversal of 13222150555153 is 35155505122231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8222602130064 + 4999548425089 = 2867508^2 + 2235967^2 .

It is a cyclic number.

It is not a de Polignac number, because 13222150555153 - 25 = 13222150555121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13222150555753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611075277576 + 6611075277577.

It is an arithmetic number, because the mean of its divisors is an integer number (6611075277577).

Almost surely, 213222150555153 is an apocalyptic number.

It is an amenable number.

13222150555153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13222150555153 is an equidigital number, since it uses as much as digits as its factorization.

13222150555153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225000, while the sum is 40.

Adding to 13222150555153 its reverse (35155505122231), we get a palindrome (48377655677384).

The spelling of 13222150555153 in words is "thirteen trillion, two hundred twenty-two billion, one hundred fifty million, five hundred fifty-five thousand, one hundred fifty-three".