Base | Representation |
---|---|
bin | 1100000001101000010111… |
… | …1010011000101011101011 |
3 | 1201211000200210020020211211 |
4 | 3000122011322120223223 |
5 | 3213112433414343032 |
6 | 44042101414533551 |
7 | 2533161231504346 |
oct | 300320572305353 |
9 | 51730623206754 |
10 | 13222156012267 |
11 | 4238537405934 |
12 | 15966613672b7 |
13 | 74bac8251c07 |
14 | 339d5489945d |
15 | 17de12ca5747 |
hex | c0685e98aeb |
13222156012267 has 2 divisors, whose sum is σ = 13222156012268. Its totient is φ = 13222156012266.
The previous prime is 13222156012249. The next prime is 13222156012283. The reversal of 13222156012267 is 76221065122231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13222156012267 - 243 = 4426062990059 is a prime.
It is a super-2 number, since 2×132221560122672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13222156012237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611078006133 + 6611078006134.
It is an arithmetic number, because the mean of its divisors is an integer number (6611078006134).
Almost surely, 213222156012267 is an apocalyptic number.
13222156012267 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222156012267 is an equidigital number, since it uses as much as digits as its factorization.
13222156012267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 13222156012267 in words is "thirteen trillion, two hundred twenty-two billion, one hundred fifty-six million, twelve thousand, two hundred sixty-seven".
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