Base | Representation |
---|---|
bin | 11110000100000110011001… |
… | …000000101110010100101111 |
3 | 122100011102000122022101211021 |
4 | 132010012121000232110233 |
5 | 114312320440114424101 |
6 | 1145114245251035011 |
7 | 36564543361104343 |
oct | 3604063100562457 |
9 | 570142018271737 |
10 | 132223135311151 |
11 | 39148575918975 |
12 | 129b589059ba67 |
13 | 58a1785252941 |
14 | 24918c35a1623 |
15 | 1044661b375a1 |
hex | 78419902e52f |
132223135311151 has 4 divisors (see below), whose sum is σ = 132241471628904. Its totient is φ = 132204798993400.
The previous prime is 132223135311119. The next prime is 132223135311233. The reversal of 132223135311151 is 151113531322231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132223135311151 - 25 = 132223135311119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132223135311101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9168148060 + ... + 9168162481.
It is an arithmetic number, because the mean of its divisors is an integer number (33060367907226).
Almost surely, 2132223135311151 is an apocalyptic number.
132223135311151 is a deficient number, since it is larger than the sum of its proper divisors (18336317753).
132223135311151 is an equidigital number, since it uses as much as digits as its factorization.
132223135311151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18336317752.
The product of its digits is 16200, while the sum is 34.
Adding to 132223135311151 its reverse (151113531322231), we get a palindrome (283336666633382).
The spelling of 132223135311151 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, one hundred thirty-five million, three hundred eleven thousand, one hundred fifty-one".
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