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132223135311151 = 721118336310541
BaseRepresentation
bin11110000100000110011001…
…000000101110010100101111
3122100011102000122022101211021
4132010012121000232110233
5114312320440114424101
61145114245251035011
736564543361104343
oct3604063100562457
9570142018271737
10132223135311151
1139148575918975
12129b589059ba67
1358a1785252941
1424918c35a1623
151044661b375a1
hex78419902e52f

132223135311151 has 4 divisors (see below), whose sum is σ = 132241471628904. Its totient is φ = 132204798993400.

The previous prime is 132223135311119. The next prime is 132223135311233. The reversal of 132223135311151 is 151113531322231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132223135311151 - 25 = 132223135311119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132223135311101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9168148060 + ... + 9168162481.

It is an arithmetic number, because the mean of its divisors is an integer number (33060367907226).

Almost surely, 2132223135311151 is an apocalyptic number.

132223135311151 is a deficient number, since it is larger than the sum of its proper divisors (18336317753).

132223135311151 is an equidigital number, since it uses as much as digits as its factorization.

132223135311151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18336317752.

The product of its digits is 16200, while the sum is 34.

Adding to 132223135311151 its reverse (151113531322231), we get a palindrome (283336666633382).

The spelling of 132223135311151 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, one hundred thirty-five million, three hundred eleven thousand, one hundred fifty-one".

Divisors: 1 7211 18336310541 132223135311151