Base | Representation |
---|---|
bin | 1100000001101000111111… |
… | …0111011001001110001011 |
3 | 1201211001010102110010020012 |
4 | 3000122033313121032023 |
5 | 3213113304142001303 |
6 | 44042130142022135 |
7 | 2533165330046552 |
oct | 300321767311613 |
9 | 51731112403205 |
10 | 13222323000203 |
11 | 42386126a0399 |
12 | 15966a927794b |
13 | 74bb23a1b245 |
14 | 339d6cb26d99 |
15 | 17de2278d5d8 |
hex | c068fdd938b |
13222323000203 has 2 divisors, whose sum is σ = 13222323000204. Its totient is φ = 13222323000202.
The previous prime is 13222323000197. The next prime is 13222323000247. The reversal of 13222323000203 is 30200032322231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13222323000203 is a prime.
It is not a weakly prime, because it can be changed into another prime (13222323000703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611161500101 + 6611161500102.
It is an arithmetic number, because the mean of its divisors is an integer number (6611161500102).
Almost surely, 213222323000203 is an apocalyptic number.
13222323000203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222323000203 is an equidigital number, since it uses as much as digits as its factorization.
13222323000203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 13222323000203 its reverse (30200032322231), we get a palindrome (43422355322434).
The spelling of 13222323000203 in words is "thirteen trillion, two hundred twenty-two billion, three hundred twenty-three million, two hundred three", and thus it is an aban number.
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