Base | Representation |
---|---|
bin | 1100000001101001000001… |
… | …1110000000100111100100 |
3 | 1201211001011010111102011020 |
4 | 3000122100132000213210 |
5 | 3213113314234414134 |
6 | 44042131143011140 |
7 | 2533165512100323 |
oct | 300322036004744 |
9 | 51731133442136 |
10 | 13222333123044 |
11 | 4238618384881 |
12 | 15966b0739ab0 |
13 | 74bb25b539a6 |
14 | 339d702000ba |
15 | 17de235dcb49 |
hex | c06907809e4 |
13222333123044 has 24 divisors (see below), whose sum is σ = 32193506735040. Its totient is φ = 4215816357984.
The previous prime is 13222333123039. The next prime is 13222333123081. The reversal of 13222333123044 is 44032133322231.
It is a super-3 number, since 3×132223331230443 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13222333122996 and 13222333123014.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23953501759 + ... + 23953502310.
It is an arithmetic number, because the mean of its divisors is an integer number (1341396113960).
Almost surely, 213222333123044 is an apocalyptic number.
It is an amenable number.
13222333123044 is an abundant number, since it is smaller than the sum of its proper divisors (18971173611996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13222333123044 is a wasteful number, since it uses less digits than its factorization.
13222333123044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47907004099 (or 47907004097 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 13222333123044 its reverse (44032133322231), we get a palindrome (57254466445275).
The spelling of 13222333123044 in words is "thirteen trillion, two hundred twenty-two billion, three hundred thirty-three million, one hundred twenty-three thousand, forty-four".
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