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1322234121034 = 25471208623511
BaseRepresentation
bin10011001111011011010…
…010111000101101001010
311200101220202202211101101
4103033123102320231022
5133130413413333114
62451232002012014
7164346123405601
oct23173322705512
94611822684341
101322234121034
1146a835766432
1219431164700a
13978bc5bc388
1447dd4470a38
15245dad9cd74
hex133db4b8b4a

1322234121034 has 8 divisors (see below), whose sum is σ = 1986977053728. Its totient is φ = 659908436460.

The previous prime is 1322234121001. The next prime is 1322234121059. The reversal of 1322234121034 is 4301214322231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13222341210342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1322234120993 and 1322234121011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604310662 + ... + 604312849.

It is an arithmetic number, because the mean of its divisors is an integer number (248372131716).

Almost surely, 21322234121034 is an apocalyptic number.

1322234121034 is a deficient number, since it is larger than the sum of its proper divisors (664742932694).

1322234121034 is a wasteful number, since it uses less digits than its factorization.

1322234121034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1208624060.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1322234121034 its reverse (4301214322231), we get a palindrome (5623448443265).

The spelling of 1322234121034 in words is "one trillion, three hundred twenty-two billion, two hundred thirty-four million, one hundred twenty-one thousand, thirty-four".

Divisors: 1 2 547 1094 1208623511 2417247022 661117060517 1322234121034