Base | Representation |
---|---|
bin | 11110000100001100111000… |
… | …110111111001111001001111 |
3 | 122100012002000212210020012021 |
4 | 132010030320313321321033 |
5 | 114312424232223233403 |
6 | 1145121401444351011 |
7 | 36565211310522256 |
oct | 3604147067717117 |
9 | 570162025706167 |
10 | 132230112321103 |
11 | 3915052619a7a5 |
12 | 129b70b90a5467 |
13 | 58a23278694b4 |
14 | 2491d8605579d |
15 | 104491e40e8bd |
hex | 784338df9e4f |
132230112321103 has 4 divisors (see below), whose sum is σ = 132230833061488. Its totient is φ = 132229391580720.
The previous prime is 132230112321101. The next prime is 132230112321113. The reversal of 132230112321103 is 301123211032231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132230112321103 - 21 = 132230112321101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132230112321101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 360094926 + ... + 360461947.
It is an arithmetic number, because the mean of its divisors is an integer number (33057708265372).
Almost surely, 2132230112321103 is an apocalyptic number.
132230112321103 is a deficient number, since it is larger than the sum of its proper divisors (720740385).
132230112321103 is an equidigital number, since it uses as much as digits as its factorization.
132230112321103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 720740384.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 132230112321103 its reverse (301123211032231), we get a palindrome (433353323353334).
The spelling of 132230112321103 in words is "one hundred thirty-two trillion, two hundred thirty billion, one hundred twelve million, three hundred twenty-one thousand, one hundred three".
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