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1322310961537 is a prime number
BaseRepresentation
bin10011001111011111111…
…000000000100110000001
311200102010010100201201221
4103033133320000212001
5133131043101232122
62451243344555041
7164351045502436
oct23173770004601
94612103321657
101322310961537
1146a875079885
12194333322a81
13979024b4627
1448000753b8d
15245e29ca6c7
hex133dfe00981

1322310961537 has 2 divisors, whose sum is σ = 1322310961538. Its totient is φ = 1322310961536.

The previous prime is 1322310961513. The next prime is 1322310961571. The reversal of 1322310961537 is 7351690132231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 875564432656 + 446746528881 = 935716^2 + 668391^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1322310961537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1322310961493 and 1322310961502.

It is not a weakly prime, because it can be changed into another prime (1322310961637) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661155480768 + 661155480769.

It is an arithmetic number, because the mean of its divisors is an integer number (661155480769).

Almost surely, 21322310961537 is an apocalyptic number.

It is an amenable number.

1322310961537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322310961537 is an equidigital number, since it uses as much as digits as its factorization.

1322310961537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 43.

The spelling of 1322310961537 in words is "one trillion, three hundred twenty-two billion, three hundred ten million, nine hundred sixty-one thousand, five hundred thirty-seven".