Base | Representation |
---|---|
bin | 1100000001101011111111… |
… | …1110001111110100000010 |
3 | 1201211010012200011012011221 |
4 | 3000122333332033310002 |
5 | 3213121432301244132 |
6 | 44042342213025254 |
7 | 2533224330235216 |
oct | 300327776176402 |
9 | 51733180135157 |
10 | 13223130103042 |
11 | 4238997242732 |
12 | 159689362522a |
13 | 74bc21cba0a2 |
14 | 33a007dc0946 |
15 | 17de6d569e97 |
hex | c06bff8fd02 |
13223130103042 has 4 divisors (see below), whose sum is σ = 19834695154566. Its totient is φ = 6611565051520.
The previous prime is 13223130102943. The next prime is 13223130103133. The reversal of 13223130103042 is 24030103132231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13106144898081 + 116985204961 = 3620241^2 + 342031^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13223130102998 and 13223130103016.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3305782525759 + ... + 3305782525762.
Almost surely, 213223130103042 is an apocalyptic number.
13223130103042 is a deficient number, since it is larger than the sum of its proper divisors (6611565051524).
13223130103042 is an equidigital number, since it uses as much as digits as its factorization.
13223130103042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6611565051523.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13223130103042 its reverse (24030103132231), we get a palindrome (37253233235273).
The spelling of 13223130103042 in words is "thirteen trillion, two hundred twenty-three billion, one hundred thirty million, one hundred three thousand, forty-two".
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