Base | Representation |
---|---|
bin | 1100000001101100010111… |
… | …1111111100100000010000 |
3 | 1201211010110201102000221222 |
4 | 3000123011333330200100 |
5 | 3213122134142232121 |
6 | 44042400224104212 |
7 | 2533226665525163 |
oct | 300330577744020 |
9 | 51733421360858 |
10 | 13223231211536 |
11 | 4238a39320a75 |
12 | 1596901465068 |
13 | 74bc39c2b2b8 |
14 | 33a0175bdada |
15 | 17de7738d0ab |
hex | c06c5ffc810 |
13223231211536 has 10 divisors (see below), whose sum is σ = 25620010472382. Its totient is φ = 6611615605760.
The previous prime is 13223231211481. The next prime is 13223231211551. The reversal of 13223231211536 is 63511213232231.
It can be written as a sum of positive squares in only one way, i.e., 9398859851536 + 3824371360000 = 3065756^2 + 1955600^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13223231211496 and 13223231211505.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 413225975345 + ... + 413225975376.
Almost surely, 213223231211536 is an apocalyptic number.
13223231211536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
13223231211536 is a deficient number, since it is larger than the sum of its proper divisors (12396779260846).
13223231211536 is an equidigital number, since it uses as much as digits as its factorization.
13223231211536 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 826451950729 (or 826451950723 counting only the distinct ones).
The product of its digits is 38880, while the sum is 35.
Adding to 13223231211536 its reverse (63511213232231), we get a palindrome (76734444443767).
The spelling of 13223231211536 in words is "thirteen trillion, two hundred twenty-three billion, two hundred thirty-one million, two hundred eleven thousand, five hundred thirty-six".
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