Base | Representation |
---|---|
bin | 111101100100110101… |
… | …1000111101110010101 |
3 | 110122022111212012001020 |
4 | 1323021223013232111 |
5 | 4131303012340000 |
6 | 140425150151353 |
7 | 12360563033304 |
oct | 1731153075625 |
9 | 418274765036 |
10 | 132232543125 |
11 | 510969068a1 |
12 | 217644b2559 |
13 | c61458b877 |
14 | 6585bb843b |
15 | 368dd5cba0 |
hex | 1ec9ac7b95 |
132232543125 has 40 divisors (see below), whose sum is σ = 220370583840. Its totient is φ = 70506888000.
The previous prime is 132232543123. The next prime is 132232543133. The reversal of 132232543125 is 521345232231.
It is not a de Polignac number, because 132232543125 - 21 = 132232543123 is a prime.
It is a super-2 number, since 2×1322325431252 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132232543123) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 12874242 + ... + 12884508.
It is an arithmetic number, because the mean of its divisors is an integer number (5509264596).
Almost surely, 2132232543125 is an apocalyptic number.
132232543125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
132232543125 is a deficient number, since it is larger than the sum of its proper divisors (88138040715).
132232543125 is an equidigital number, since it uses as much as digits as its factorization.
132232543125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17159 (or 17144 counting only the distinct ones).
The product of its digits is 43200, while the sum is 33.
Adding to 132232543125 its reverse (521345232231), we get a palindrome (653577775356).
The spelling of 132232543125 in words is "one hundred thirty-two billion, two hundred thirty-two million, five hundred forty-three thousand, one hundred twenty-five".
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