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132233033033113 is a prime number
BaseRepresentation
bin11110000100001111100110…
…111101100010010110011001
3122100012100120102121202212011
4132010033212331202112121
5114313001222424024423
61145123003341345521
736565343554255525
oct3604174675422631
9570170512552764
10132233033033113
1139151794925981
12129b77932682a1
1358a26a19ac75c
142492181cdcd85
151044a40a40b0d
hex7843e6f62599

132233033033113 has 2 divisors, whose sum is σ = 132233033033114. Its totient is φ = 132233033033112.

The previous prime is 132233033033099. The next prime is 132233033033119. The reversal of 132233033033113 is 311330330332231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76789327754304 + 55443705278809 = 8762952^2 + 7446053^2 .

It is a cyclic number.

It is not a de Polignac number, because 132233033033113 - 25 = 132233033033081 is a prime.

It is a super-3 number, since 3×1322330330331133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132233033033119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66116516516556 + 66116516516557.

It is an arithmetic number, because the mean of its divisors is an integer number (66116516516557).

Almost surely, 2132233033033113 is an apocalyptic number.

It is an amenable number.

132233033033113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132233033033113 is an equidigital number, since it uses as much as digits as its factorization.

132233033033113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 31.

Adding to 132233033033113 its reverse (311330330332231), we get a palindrome (443563363365344).

The spelling of 132233033033113 in words is "one hundred thirty-two trillion, two hundred thirty-three billion, thirty-three million, thirty-three thousand, one hundred thirteen".