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132236044763 is a prime number
BaseRepresentation
bin111101100100111100…
…0011110100111011011
3110122022202110002101112
41323021320132213123
54131304411413023
6140425353210535
712360634556204
oct1731170364733
9418282402345
10132236044763
1151098888709
1221765700a4b
13c615216644
14658644a5ab
15368e300478
hex1ec9e1e9db

132236044763 has 2 divisors, whose sum is σ = 132236044764. Its totient is φ = 132236044762.

The previous prime is 132236044729. The next prime is 132236044769. The reversal of 132236044763 is 367440632231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132236044763 - 230 = 131162302939 is a prime.

It is a super-3 number, since 3×1322360447633 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132236044763.

It is not a weakly prime, because it can be changed into another prime (132236044769) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66118022381 + 66118022382.

It is an arithmetic number, because the mean of its divisors is an integer number (66118022382).

Almost surely, 2132236044763 is an apocalyptic number.

132236044763 is a deficient number, since it is larger than the sum of its proper divisors (1).

132236044763 is an equidigital number, since it uses as much as digits as its factorization.

132236044763 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 435456, while the sum is 41.

Adding to 132236044763 its reverse (367440632231), we get a palindrome (499676676994).

The spelling of 132236044763 in words is "one hundred thirty-two billion, two hundred thirty-six million, forty-four thousand, seven hundred sixty-three".